Design Matrix Continuous Variable
To fill a single column in the design matrix with sequential values (i.e., 1, 2, 3, ...), select the FillCol, Continuous choices. The current column is the one containing the highlighted cell. This command is useful in testing for trends in parameters, i.e., models such as S(T). As an example, suppose the following design matrix is on the screen, with the current column shown as the one with the underlined value.
|
1 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
|
0 |
1 |
0 |
0 |
0 |
0 |
0 |
0 |
|
0 |
0 |
1 |
0 |
0 |
0 |
0 |
0 |
|
0 |
0 |
0 |
1 |
0 |
0 |
0 |
0 |
|
0 |
0 |
0 |
0 |
1 |
0 |
0 |
0 |
|
0 |
0 |
0 |
0 |
0 |
1 |
0 |
0 |
|
0 |
0 |
0 |
0 |
0 |
0 |
1 |
0 |
|
0 |
0 |
0 |
0 |
0 |
0 |
0 |
1 |
After the column is filled with sequential values, the matrix would look like this.
|
1 |
1 |
0 |
0 |
0 |
0 |
0 |
0 |
|
0 |
2 |
0 |
0 |
0 |
0 |
0 |
0 |
|
0 |
3 |
1 |
0 |
0 |
0 |
0 |
0 |
|
0 |
4 |
0 |
1 |
0 |
0 |
0 |
0 |
|
0 |
5 |
0 |
0 |
1 |
0 |
0 |
0 |
|
0 |
6 |
0 |
0 |
0 |
1 |
0 |
0 |
|
0 |
7 |
0 |
0 |
0 |
0 |
1 |
0 |
|
0 |
8 |
0 |
0 |
0 |
0 |
0 |
1 |